[Corso Python3] Ecco, così funziona... (è quello del sito, molto bello. Il programma intendo)

[alessandro medici]

def int_to_roman(input):
    """ Convert an integer to a Roman numeral. """

    #if not isinstance(input, type(1)):
        #raise TypeError, "expected integer, got %s" % type(input)
    #if not 0 < input < 4000:
        #raise ValueError, "Argument must be between 1 and 3999"
    ints = (1000, 900,  500, 400, 100,  90, 50,  40, 10,  9,   5,  4,   1)
    nums = ('M',  'CM', 'D', 'CD','C', 'XC','L','XL','X','IX','V','IV','I')
    result = []
    for i in range(len(ints)):
        count = int(input / ints[i])
        result.append(nums[i] * count)
        input -= ints[i] * count
    return ''.join(result)

def roman_to_int(input):
    """ Convert a Roman numeral to an integer. """

    #if not isinstance(input, type("")):
        #raise TypeError, "expected string, got %s" % type(input)
    input = input.upper(  )
    nums = {'M':1000, 'D':500, 'C':100, 'L':50, 'X':10, 'V':5, 'I':1}
    sum = 0
    for i in range(len(input)):
        try:
            value = nums[input[i]]
            # If the next place holds a larger number, this value is
negative
            if i+1 < len(input) and nums[input[i+1]] > value:
                sum -= value
            else: sum += value
        except KeyError:
            pass
    # easiest test for validity...
    print('vado a romano con ', sum)
    if int_to_roman(sum) == input:
        print(sum)
    else:
        print('errore')

while True:
a = input('Romano:')
if a == 'e':
break
roman_to_int(a)
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